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Standard VI
Mathematics
Question
Lay down the positions of the points whose polar coordinates are
(
−
2
a
,
−
2
π
3
)
Open in App
Solution
Verified by Toppr
Polar co-ordinates are
(
−
2
a
,
−
−
2
π
3
)
Then,
r
=
−
2
a
and
θ
=
−
2
π
3
x
=
r
c
o
s
θ
=
(
−
2
a
)
c
o
s
−
2
π
3
=
a
x
=
r
s
i
n
θ
=
(
−
2
a
)
s
i
n
−
2
π
3
=
√
3
a
.
Thus, the Cartesian co-ordinates are
(
a
,
√
3
a
)
.
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