Length of a rectangle exceeds its breadth by 5 mathrm - m - If the perimeter of the rectangle is 90 mathrm - m - Find its length and breadth-

Question

Toppr Admin · Accepted Answer

Let breadth of rectangle be x-Then- its length - x-5Now- Perimeter - 90 m2-x-x-5-902x-5-452x-40x-20-xA0-mTherefore- length - 25-xA0-m and breadth - 20-xA0-m-

Length of a rectangle exceeds its breadth by $5 m$ . If the perimeter of the rectangle is $90 m$ . Find its length and breadth.

Let breadth of rectangle be $x$ .
Then, its length = $x + 5$
Now, Perimeter = 90 m
$2 (x + x + 5) = 90$
$2 x + 5 = 45$
$2 x = 40$
$x = 20 m$
Therefore, length = $25 m$ and breadth = $20 m$ .

Length of a rectangle exceeds its breadth by 5m. If the perimeter of the rectangle is 90m. Find its length and breadth.

Let breadth of rectangle be x.Then, its length = x+5Now, Perimeter = 90 m2(x+x+5)=902x+5=452x=40x=20 mTherefore, length = 25 m and breadth = 20 m.

Length of a rectangle exceeds its breadth by $5 m$ . If the perimeter of the rectangle is $90 m$ . Find its length and breadth.

Let breadth of rectangle be $x$ .
Then, its length = $x + 5$
Now, Perimeter = 90 m
$2 (x + x + 5) = 90$
$2 x + 5 = 45$
$2 x = 40$
$x = 20 m$
Therefore, length = $25 m$ and breadth = $20 m$ .