As C is the mid point of arc ACB,
Arc length AC=CB and radius is same for both arc,So
∠CAD=∠CBD
It is also clear that ∠ACB=90o as angle on circumference of half-circle.
So ∠CAD=∠CBD=45o
it means AD=DC=DB=1
AC2=AD2+DC2=1+1=2
AC=√2 which is the diameter of arc T.
Area of shaded region = area of semicircle T−area of ΔADC
=12Π(AC2)2−12AD×DC
=12Π(√22)2−121×1
=π4−12
The area of the region inside the semicircle TT but outside SS is
= area of semicircle T−area of shaded region
=π4−(π4−12)
=12
Option B is correct.