Let f:[−25,25]→R where f(x) is defined by f(x)=sinnx+[x4a] be an odd function, if n is odd. Then the set of values of the parameter a is/are ([⋅] denotes greatest integer function)
(−25,25)−{0}
[390625,∞)
(−25,0)
(390625,∞)
A
(390625,∞)
B
(−25,0)
C
(−25,25)−{0}
D
[390625,∞)
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Solution
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Since n is odd, therefore sinn(−x)=−sinnx For an odd function, f(x)=−f(−x) −(sinn(−x)+[(−x)4a])=sinnx+[x4a] ⇒sinn(x)−[x4a]=sinnx+[x4a] ⇒[x4a]=0 ⇒[x4a]<1 ⇒a>254 since x∈[−25,25] ⇒a>390625
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