Let g:[−2,2]→R where g(x)=x3+tanx+[x2+1P] be an odd function , then the value of the parameter P satisfies (Note : [a] denotes the greatest integer less than or equal to a)
−5<P<5
−5<P<0
P<5
P>5
A
−5<P<0
B
−5<P<5
C
P<5
D
P>5
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Solution
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Let h(x)=[x2+1P].
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