Question

Let f:(0,)R be given by f(x)=x1/xe(t+1t)dtt, then

A
f(x) is monotonically increasing on [1,)
B
f(x) is monotonically decreasing on (0, 1)
C
f(x)+f(1x)=0, for all x(0,)
D
f(2x) is an odd function of x on R
Solution
Verified by Toppr


1486917_113809_ans_d92a9d99ad644f9dbb04ca2021f41d69.jpg

Was this answer helpful?
0
Similar Questions
Q1

Let f(x)=2x2ln|x|,x0,thenf(x) is

View Solution
Q2

Let f:(0,)R be a differentiable function such that
f(x)=2f(x)x for all xϵ(0,) and f(1)1. Then


View Solution
Q3

Let f(x)= {x^2 ; x>=0

{ax ; x<0

Find a for which f(x) is monotonically increasing function at x=0.

View Solution
Q4

Let g(x)=x0f(t)dt and f(x) satisfies the equation f(x+y)=f(x)+f(y)+2xy1 for all x, yϵR and f(0)=2 then


View Solution
Q5

For x>0, let f(x)=x1log t1+t dt. Then f(x)+f(1x) is equal to


View Solution
Solve
Guides