Let f(x) and g(x) are two function of x such that f(x)+g(x)=ex and f(x)−g(x)=e−x then
g(x) is an odd function
f(x) is an odd function
f(x) is an even function
g(x) is an even function
A
f(x) is an odd function
B
g(x) is an odd function
C
f(x) is an even function
D
g(x) is an even function
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Solution
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f(x)+g(x)=ex...(i) f(x)−g(x)=e−x ...(ii) Adding both the equations, we get f(x)=ex+e−x2
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