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Question

Let the distance between vectors are given as follows :
(i)4i+3j6k,2i+jk be k
(ii)2i+3j+5k,7ik be mn
Find k(mn) ?
  1. 20
  2. 21
  3. 22
  4. 23

A
21
B
20
C
22
D
23
Solution
Verified by Toppr

(i) Distance between 4i+3j6k and 2i+jk is given by (4+2)2+(31)2+(6+1)2=36+4+25=65
k=65

(ii) Distance between 2i+3j+5k and 7ik would be (27)2+(3)2+(5+1)2=81+9+36=126=314
m=3,n=14

k(mn)=65(3×14)=6542=23

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