Question

# Let the refractive index of a denser medium with respect to a rare medium be N12 and its critical angle θC . At an angle of incidence A when light is travelling from denser medium to rarer medium, a part of the light is reflected and the rest is refracted and the angle between reflected and refracted rays is 90o. Angle A is given by :

A
tan1(sinθC)
B
1tan1(sinθC)
C
1cos1(sinθC)
D
cos1(sinθC)
Solution
Verified by Toppr

#### n12=ndnrsinθsin90=n2n3sinisinR=n2n1sini=sinrsinrsinR=n2n1=sinθcsin90sinrcosr=sinθccosrtanr=sinθcr=tan−1(sinθc)

4
Similar Questions
Q1

Light from a denser medium 1 passes to a rarer medium 2. When the angle of incidence is θ, the partially reflected and refracted rays are mutually perpendicular. The critical angle will be

View Solution
Q2

A ray of light from denser medium strikes a rarer medium at angle of incidence i. The reflected and refracted rays make an angle of 90o with each other. The angle of reflection and refraction are r and r. The critical angle is

View Solution
Q3

A ray of light from a denser medium strikes a rare medium at an angle of incidence i (see figure). The reflected and refracted rays make and angle of 90 with each other. The angles of reflection and refraction are r and r. The critical angle is

View Solution
Q4
A ray of light from a denser medium strikes a rarer medium at an angle of incidence i If the angle of reflection is γ and the angle of refraction is γ and the reflected and refracted rays make an angle of 90o with each other, then the critical angle will be:
View Solution
Q5

A ray of light from a denser medium strikes a rarer medium at an angle of incidence i. If the reflected and refracted rays are mutually perpendicular to each other then the critical angle is :

View Solution
Solve
Guides