Let the of the first three terms of an A-P- be 39 and the of its last four terms be 178- If the first term of this A-P- is 10- then the median of the A-P- is-26-53129-528

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Toppr Admin · Accepted Answer

Let the first three terms of the A-P- be a-x2212-d-a-a-dGiven a-x2212-d-10-1-Also given a-x2212-d-a-a-d-39-x21D2-3a-39-2-

Let the sum of the first three terms of an A.P. be $39$ and the sum of its last four terms be $178$ . If the first term of this A.P. is $10$ , then the median of the A.P. is:
$26.5$
$31$
$29.5$
$28$

Let the first three terms of the A.P. be $a - d, a, a + d$
Given $a - d = 10 . . . (1)$
Also given $a - d + a + a + d = 39$
$\Rightarrow 3 a = 39 . . . (2)$

Let the sum of the first three terms of an A.P. be 39 and the sum of its last four terms be 178. If the first term of this A.P. is 10, then the median of the A.P. is:26.53129.528

Let the first three terms of the A.P. be a−d,a,a+dGiven a−d=10...(1)Also given a−d+a+a+d=39⇒3a=39...(2)

Let the sum of the first three terms of an A.P. be $39$ and the sum of its last four terms be $178$ . If the first term of this A.P. is $10$ , then the median of the A.P. is:
$26.5$
$31$
$29.5$
$28$

Let the first three terms of the A.P. be $a - d, a, a + d$
Given $a - d = 10 . . . (1)$
Also given $a - d + a + a + d = 39$
$\Rightarrow 3 a = 39 . . . (2)$