Let V-0 be the potential the origin in an electric field overset-rightarrow-E-E-xhat-i-E-yhat-j- The potential the point -x-y- is-V-0-x-E-x-y-E-y-V-0-x-E-x-y-E-y-x-E-x-y-E-y-V-0left-sqrt-x-2-y-2-right-sqrt-E-x-2-E-y-2-V-0

Question

Toppr Admin · Accepted Answer

Let V0 be the potential at the origin in an electric field →E=Ex^i+Ey^j. The potential at the point (x,y) is:V0−xEx−yEyV0+xEx+yEyxEx+yEy−V0(√x2+y2)√E2x+E2y−V0

Let $V_{0}$ be the potential at the origin in an electric field $\to E = E_{x}^i + E_{y}^j$ . The potential at the point $(x, y)$ is:
$V_{0} -_{x} E_{x} -_{y} E_{y}$
$V_{0} +_{x} E_{x} +_{y} E_{y}$
$_{x} E_{x} +_{y} E_{y} - V_{0}$
$(\sqrt{x^{2} + y^{2}}) \sqrt{E_{x}^{2} + E_{y}^{2}} - V_{0}$