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Let $$v_1$$ be the the volume of a given right circular cone with $$O$$ as the centre of the base and $$A$$ as its apex. Let $$v_2$$ be the maximum volume of the right circular cone whose apex is $$O$$ and whose base is parallel to the base of the given cone. The the ratio $$\dfrac{v_2}{v_1}$$ is:

A
$$\dfrac{3}{25}$$
B
$$\dfrac{4}{9}$$
C
$$\dfrac{4}{27}$$
D
$$\dfrac{8}{27}$$
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Solution
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Correct option is A. $$\dfrac{3}{25}$$

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