Let x-dfrac - p - q - be a rational number- such that the prime factorization of q is of the form 2-n 5-m- where n- m are non-negative integers- Then x has a decimal expansion which terminates-TrueFalseNeitherEither

Question

Let x-dfrac - p - q -  be a rational number- such that the prime factorization of q is of the form 2-n 5-m- where n- m are non-negative integers- Then x has a decimal expansion which terminates-TrueFalseNeitherEither

Toppr Admin · Accepted Answer

The form of q is 2n-x2217-5mq can be 1-2-5-10-20-40-Any integer divided by these numbers-xA0-will always give a terminating decimal number-

Let $x = \frac{p}{q}$ be a rational number, such that the prime factorization of $q$ is of the form $2^{n} 5^{m}$ , where $n, m$ are non-negative integers. Then $x$ has a decimal expansion which terminates.
True
False
Neither
Either

The form of q is $2^{n} * 5^{m}$
q can be $1, 2, 5, 10, 20, 40....$
Any integer divided by these numbers will always give a terminating decimal number.

Let x=pq be a rational number, such that the prime factorization of q is of the form 2n5m, where n,m are non-negative integers. Then x has a decimal expansion which terminates.TrueFalseNeitherEither

The form of q is 2n∗5mq can be 1,2,5,10,20,40....Any integer divided by these numbers will always give a terminating decimal number.

Let $x = \frac{p}{q}$ be a rational number, such that the prime factorization of $q$ is of the form $2^{n} 5^{m}$ , where $n, m$ are non-negative integers. Then $x$ has a decimal expansion which terminates.
True
False
Neither
Either

The form of q is $2^{n} * 5^{m}$
q can be $1, 2, 5, 10, 20, 40....$
Any integer divided by these numbers will always give a terminating decimal number.