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Standard XII
Mathematics
Question
Let
f
(
x
)
=
{
sin
x
,
x
≠
n
π
2
,
x
=
n
π
, where
n
ϵ
Z
and
g
(
x
)
=
{
x
2
+
1
,
x
≠
2
3
,
x
=
2
.
Then
lim
x
→
0
g
(
f
(
x
)
)
is
0
1
3
none of these
A
none of these
B
0
C
1
D
3
Open in App
Solution
Verified by Toppr
lim
x
→
0
+
g
(
f
(
x
)
)
=
lim
x
→
0
+
g
(
sin
x
)
=
lim
x
→
0
+
(
sin
2
x
+
1
)
=
0
+
1
=
1
lim
x
→
0
−
g
(
f
(
x
)
)
=
lim
x
→
0
−
g
(
sin
x
)
=
lim
x
→
0
−
(
sin
2
x
+
1
)
=
1
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Similar Questions
Q1
Let
f
(
x
)
=
{
sin
x
,
x
≠
n
π
2
,
x
=
n
π
, where
n
ϵ
Z
and
g
(
x
)
=
{
x
2
+
1
,
x
≠
2
3
,
x
=
2
.
Then
lim
x
→
0
g
(
f
(
x
)
)
is
View Solution
Q2
f
(
x
)
=
{
sin
x
;
x
≠
n
π
,
n
=
0
,
±
1
,
±
2
,
±
3.....
2
;
o
t
h
e
r
w
i
s
e
and
g
(
x
)
=
{
x
2
+
1
;
x
≠
0
4
;
x
=
0
.
Then
lim
x
→
0
g
(
f
(
x
)
)
is
View Solution
Q3
If
f
(
x
)
=
{
x
+
1
,
x
>
0
2
−
x
,
x
≤
0
and
g
(
x
)
=
⎧
⎪
⎨
⎪
⎩
x
+
3
,
x
<
1
x
2
−
2
x
−
2
,
1
≤
x
<
2
x
−
5
,
x
≥
2
, then the value of
lim
x
→
0
g
(
f
(
x
)
)
is
View Solution
Q4
Let
f
(
x
)
=
{
x
+
1
,
x
>
0
2
−
x
,
x
≤
0
and
g
(
x
)
=
⎧
⎪
⎨
⎪
⎩
x
+
3
,
x
<
1
x
2
−
2
x
−
2
,
1
≤
x
<
2
x
−
5
,
x
≥
2
.
Find
lim
x
→
0
g
(
f
(
x
)
)
.
View Solution
Q5
If
f
(
x
)
=
{
s
i
n
x
,
x
≠
n
π
,
n
ϵ
I
2
,
o
t
h
e
r
w
i
s
e
and
g
(
x
)
=
⎧
⎪
⎨
⎪
⎩
x
2
+
1
,
x
≠
0
,
2
4
,
x
=
0
5
,
x
=
2
, then
l
i
m
x
→
0
g
{
f
(
x
)
}
View Solution