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Question

lf limx0(cos4x+acos2x+bx4) is finite then the value of a,b respectively are
  1. 5, 4
  2. 54
  3. 4, 3
  4. 4, 5

A
5, 4
B
54
C
4, 3
D
4, 5
Solution
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limx0(cos4x+acos2x+bx4)

As x0, denominator tends to 0, so the numerator also tends to 0.

limx0cos4x+acos2x+b=0
at x=0cos4x=1,cos2x=1
1+a+b=0
a+b=1
Now, put a=4
b=3
Option C satisfies above equation.

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