Light falls normal incidence on one face of a glass prism of refractive index sqrt-2- Then the angle of emergence when the angle of the prism is 45-circ-45-circ-60-circ-75-circ-90-circ-

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Toppr Admin · Accepted Answer

-x3BC-xD7-sin45-sinr-xD7-1-x221A-2-xD7-1-x221A-2-sinr-x21D2-r-90-x2218-

Light falls at normal incidence on one face of a glass prism of refractive index $\sqrt{2}$ . Then the angle of emergence when the angle of the prism is 45 $^{\circ}$
45 $^{\circ}$
60 $^{\circ}$
75 $^{\circ}$
90 $^{\circ}$

$μ \times s i n 45 = s i n r \times 1$
$\sqrt{2} \times \frac{1}{\sqrt{2}} = s i n r$

$\Rightarrow r = 90^{\circ}$

Light falls at normal incidence on one face of a glass prism of refractive index √2. Then the angle of emergence when the angle of the prism is 45∘45∘60∘75∘90∘

μ×sin45=sinr×1√2×1√2=sinr⇒r=90∘

Light falls at normal incidence on one face of a glass prism of refractive index $\sqrt{2}$ . Then the angle of emergence when the angle of the prism is 45 $^{\circ}$
45 $^{\circ}$
60 $^{\circ}$
75 $^{\circ}$
90 $^{\circ}$

$μ \times s i n 45 = s i n r \times 1$
$\sqrt{2} \times \frac{1}{\sqrt{2}} = s i n r$

$\Rightarrow r = 90^{\circ}$