Light from a point in air falls on a convex spherical glass surface of refractive index 1-5 and radius of curvature 80cm- The distance of light from the glass surface is 100cm- At what position is the image formed-

Question

Toppr Admin · Accepted Answer

By this formula -n2-v - n1-u - -n2-n1-R-1-5-v - -1-5-1-20 - 1-100-1-5-v - 5-200 - 1-100-1-5-v - 5-2-200-1-5-v - 3-200-v - 1-5x200-3 - 100

Light from a point source in air falls on a convex spherical glass surface of refractive index $1.5$ and radius of curvature $80$ cm. The distance of light source from the glass surface is $100$ cm. At what position is the image formed?

By this formula
n2/v - n1/u = (n2-n1)/R
1.5/v = (1.5-1)/20 + 1/-100
1.5/v = 5/200 - 1/100
1.5/v = 5-2/200
1.5/v = 3/200
v = 1.5x200/3 = 100

Light from a point source in air falls on a convex spherical glass surface of refractive index 1.5 and radius of curvature 80cm. The distance of light source from the glass surface is 100cm. At what position is the image formed?

By this formula n2/v - n1/u = (n2-n1)/R 1.5/v = (1.5-1)/20 + 1/-100 1.5/v = 5/200 - 1/100 1.5/v = 5-2/200 1.5/v = 3/200 v = 1.5x200/3 = 100

Light from a point source in air falls on a convex spherical glass surface of refractive index $1.5$ and radius of curvature $80$ cm. The distance of light source from the glass surface is $100$ cm. At what position is the image formed?

By this formula
n2/v - n1/u = (n2-n1)/R
1.5/v = (1.5-1)/20 + 1/-100
1.5/v = 5/200 - 1/100
1.5/v = 5-2/200
1.5/v = 3/200
v = 1.5x200/3 = 100