Question

Light is incident on a glass block as shown in Fig. If θ1 is increased slightly, what happens to θ2?
159180_670cb6eaaa704aa7bf3e16326e4c2aa1.png

A
θ2 also increases slightly
B
θ2 is unchanged
C
θ2 decreases slightly
D
θ2 changes abruptly, since the ray experience total internal reflection
Solution
Verified by Toppr

if θ1 and θ2 are angle of incidence and angle of refraction respectively for a interface then according to snell's law ,
μ1sinθ1=μ2sinθ2
i.e, sinθ1sinθ2
θ1θ2
as the θ1 increases the refracting angle at 1st interface increases this results in decrease of incident angle on 2nd interface which in turn decreases the refreacting angle at 2nd interface i.e, θ2 decreases

Was this answer helpful?
0
Similar Questions
Q1

If θ1, θ2, θ3........,θn are in A.P., whose common difference is d, then,
sec θ1 sec θ2+sec θ2 sec θ3+..........+sec θn1 sec θn=

View Solution
Q2

If tan θ1, tan θ2, tan θ3 are the real roots of x3(a+1)x2+(ba)xb=0 where θ1, θ2, θ3 are acute then θ1+θ2+θ3=


View Solution
Q3

If θ1 and θ2 be the angles which the lines (x2+y2)(cos2 θ sin2 α+sin2θ)=(x tan αy sin θ)2 make with the axis of x, then if θ=π6, tan θ1+tan θ2 is equal to

View Solution
Q4

Contact angle of different liquids on pure glass surface are θ1, θ2 and θ3 and their wettability are represented as w1, w2 and w3 respectively. If θ1>θ2>θ3, then

View Solution
Q5

A student while doing the experiment on tracing the path of a ray of light passing through a rectangular glass slab measured the three angles marked as θ1, θ2 and θ3 in the figure.



His measurements could be correct if he were to find:
(1) θ1 < θ2 < θ3
(2) θ1 < θ2 but θ1 = θ3
(3) θ1 > θ2 > θ3
(4) θ1 > θ2 but θ2 = θ3

View Solution
Solve
Guides