Light of wave length 5000 Angstrom falls on a sensitive plate with photoelectric work function of 1.9 eV. The maximum kinetic energy of the photo electron emitted will be..
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Updated on : 2022-09-05
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Correct option is C)
Work function of plate ϕ=1.9eV Wavelength of incident photon λ=5000Ao=500nm Energy of the incident photon Eincident=λ(innm)1240eV ⟹Eincident=5001240=2.48eV Maximum kinetic energy of photon emitted K.Emax=Eincident−ϕ ⟹K.Emax=2.48−1.9=0.58eV
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