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Standard XII
Mathematics
Question
l
i
m
z
→
1
z
1
/
3
−
1
z
1
/
6
−
1
Open in App
Solution
Verified by Toppr
lim
z
→
1
z
1
3
−
1
z
1
6
−
1
=
lim
z
→
1
z
1
3
−
1
z
−
1
z
1
6
−
1
z
−
1
=
1
3
×
1
−
2
3
1
6
×
1
−
5
6
since
lim
x
→
a
x
n
−
a
n
x
−
a
=
n
a
n
−
1
=
6
3
=
2
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Q2
Evaluate the given limit :
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Q3
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Q4
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Q5
If z
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View Solution