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Question
l
i
m
z
→
1
z
1
/
6
−
1
z
1
/
3
−
1
Hard
Open in App
Solution
Verified by Toppr
lim
z
→
1
z
6
1
−
1
z
3
1
−
1
=
lim
z
→
1
z
−
1
z
6
1
−
1
z
−
1
z
3
1
−
1
=
6
1
×
1
6
−
5
3
1
×
1
3
−
2
since
lim
x
→
a
x
−
a
x
n
−
a
n
=
n
a
n
−
1
=
3
6
=
2
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