Magnetic field in a plane electromagnetic wave is given by
$\to B = B_{0} s i n (k x + ω t)^j T$
Expression for corresponding electric field will be :
Where c is speed of light.
$\to E = B_{0} c sin (k x + ω t)^k V / m$
$\to E = - B_{0} c sin (k x + ω t)^k V / m$
$\to E = \frac{B_{0}}{c} sin (k x + ω t)^k V / m$
$\to E = B_{0} c sin (k x - ω t)^k V / m$

Question

Toppr Admin · Accepted Answer

-x2192-E-x2192-B-C-x2192-B-B0sin-kx-x3C9-t-x2192-E-B0Csin-kx-x3C9-t-k V-m

Magnetic field in a plane electromagnetic wave is given by →B=B0sin(kx+ωt)^jTExpression for corresponding electric field will be :Where c is speed of light.→E=B0csin(kx+ωt)^kV/m→E=−B0csin(kx+ωt)^kV/m→E=B0csin(kx+ωt)^kV/m→E=B0csin(kx−ωt)^kV/m