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Standard VII
Mathematics
Question
Mark the correct options:
{
(
1
3
)
−
2
−
(
1
2
)
−
3
}
+
(
1
4
)
−
2
=
17
[
(
−
2
)
−
2
]
−
3
=
128
[
(
3
−
7
+
3
−
10
)
×
3
−
5
]
0
=
1
(
3
7
)
−
5
×
(
7
11
)
−
4
×
(
11
3
)
−
4
=
7
A
{
(
1
3
)
−
2
−
(
1
2
)
−
3
}
+
(
1
4
)
−
2
=
17
B
(
3
7
)
−
5
×
(
7
11
)
−
4
×
(
11
3
)
−
4
=
7
C
[
(
3
−
7
+
3
−
10
)
×
3
−
5
]
0
=
1
D
[
(
−
2
)
−
2
]
−
3
=
128
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Solution
Verified by Toppr
A :
=
(
3
2
−
2
3
)
+
4
2
=
(
9
−
8
)
+
16
=
17
B :
=
(
7
3
)
5
×
(
11
7
)
4
×
(
3
11
)
4
=
7
3
C :
=
1
Because any value of power is
0
have value equal to
1
.
D :
=
(
−
2
)
6
=
64
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