Question

Open in App

Updated on : 2022-09-05

Solution

Verified by Toppr

Correct option is C)

For $B$, time taken to move up is given by , $t_{1}=u/a$ ($∴$ the relation $v=u+at$ here becomes $0=u−at_{1}$).

Distance moved up is given by the relation $0=u_{2}−2aS$

i.e $S=u_{2}/2a$

For coming down the inclined plane for $S=21 at_{2}$

and $t_{2}=a2S $

or $t_{2}=a.2a2u_{2} =au $

But $au =t_{1}$, then

$t_{1}+t_{2}=3$ or $a2u =3$ or

$u=23a $ or

$u=23 ×4=6ms_{−1}$

Solve any question of Motion in a Straight Line with:-

Was this answer helpful?

0

0