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Standard XII
Mathematics
Question
Match List I with List II and select the correct answer using the codes given below the lists:
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Solution
Verified by Toppr
A
.
→
(
4
)
;
B
.
→
(
2
)
;
C
.
→
(
1
)
;
D
.
→
(
3
)
A
.
K
E
=
3
2
K
T
⇒
[
M
L
2
T
−
2
]
=
K
′
[
K
]
⇒
K
′
=
[
M
L
2
T
−
2
K
−
1
]
B
.
F
=
6
π
η
r
v
⇒
[
M
L
T
−
2
]
=
η
[
L
]
[
L
T
−
1
]
⇒
η
=
[
M
L
−
1
T
−
1
]
C
.
E
=
h
f
⇒
[
M
L
2
T
−
2
]
=
h
[
T
]
⇒
h
=
[
M
L
2
T
−
1
]
D
.
d
Q
d
t
=
K
′
A
(
Δ
T
)
Δ
x
⇒
[
M
L
2
T
−
2
]
[
T
]
=
k
[
L
2
]
[
K
′
]
[
L
]
K
′
=
[
M
L
T
−
3
K
−
1
]
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