Match List-1 with List-2- List -1 List-2 A- Aq- Solution of NaCl 1-Acidic buffer B- Aq- Solution of CH-3COONa 2-Acidic solution C- Aq- Solution of NH-4-Cl 3- Basic solution D- Aq- Solution of CH-3-COOH along with CH-3-COONa 4-Neutral solution A-1- B-2 - C-3- D-4A-4 - B-3- C-2- D-1A-3- B- 4- C-2- D-1A-4- B-3- C-1- C-2

Question

Toppr Admin · Accepted Answer

NaCl is a salt of strong acid HCl and strong base NaOH- It does not undergo hydrolysis in water- Hence its aqueous solution is neutral-Sodium acetate is a salt of strong base sodium hydroxide and weak acid acetic acid- Its solution is basic in nature-Ammonium chloride is the salt of strong acid HCl and weak base ammonium hydroxide- Its solution is acidic in nature-A mixture of acetic acid and sodium acetate is an acidic buffer- Its aqueous solution is acidic in nature-Thus-xA0-A-4 - B-3- C-2- D-1Hence- the correct option is B

List -1	List-2
A) Aq. Solution of NaCl	1)Acidic buffer
B) Aq. Solution of $C H_{3} C O O N a$	2)Acidic solution
C) Aq. Solution of $N H_{4} C l$	3) Basic solution
D) Aq. Solution of $C H_{3} C O O H$ along with $C H_{3} C O O N a$	4)Neutral solution

List -1	List-2
A) Aq. Solution of NaCl	1)Acidic buffer
B) Aq. Solution of $C H_{3} C O O N a$	2)Acidic solution
C) Aq. Solution of $N H_{4} C l$	3) Basic solution
D) Aq. Solution of $C H_{3} C O O H$ along with $C H_{3} C O O N a$	4)Neutral solution

List-I (Inequality)	List-II (Solution set)
A) $x^{2} - 4 x + 3 > 0$	1) $(3, 4)$
B) $x^{2} - 5 x + 6 \leq 0$	2) $(- 1, 1) \cup (2, 4)$
C) $x^{2} + 6 x - 27 > 0, - x^{2} + 3 x + 4 > 0$	3) $(- \infty, 1) \cup (3, \infty)$
D) $x^{2} - 3 x - 4 < 0, x^{2} - 3 x + 2 > 0$	4) $[3, 4]$
	5) $[2, 3]$