Match the column I with column II and mark the appropriate choice.
Column I Column II
$(A)$ $C H_{3} N H_{2} + C H C l_{3} + K O H Δ - \to$ $(i)$ $C H_{3} N H_{2}$
$(B)$ $C H_{3} C O N H_{2} + B r_{2} + K O H \to$ $(i i)$ $C H_{3} O H$
$(C)$ $C H_{3} N H_{2} + N a N O_{2} + H C l \to$ $(i i i)$ $C H_{3} N H C H_{3}$
$(D)$ $C H_{3} N C + 4 H P t - \to$ $(i v)$ $C H_{3} N C$

$(A) \to (i), (B) \to (i i), (C) \to (i i i), (D) \to (i v)$
$(A) \to (i v), (B) \to (i), (C) \to (i i), (D) \to (i i i)$
$(A) \to (i i i), (B) \to (i v), (C) \to (i), (D) \to (i i)$
$(A) \to (i i), (B) \to (i i i), (C) \to (i v), (D) \to (i)$

Question

Match the column I with column II and mark the appropriate choice.
Column I Column II
$(A)$ $C H_{3} N H_{2} + C H C l_{3} + K O H Δ - \to$ $(i)$ $C H_{3} N H_{2}$
$(B)$ $C H_{3} C O N H_{2} + B r_{2} + K O H \to$ $(i i)$ $C H_{3} O H$
$(C)$ $C H_{3} N H_{2} + N a N O_{2} + H C l \to$ $(i i i)$ $C H_{3} N H C H_{3}$
$(D)$ $C H_{3} N C + 4 H P t - \to$ $(i v)$ $C H_{3} N C$

$(A) \to (i), (B) \to (i i), (C) \to (i i i), (D) \to (i v)$
$(A) \to (i v), (B) \to (i), (C) \to (i i), (D) \to (i i i)$
$(A) \to (i i i), (B) \to (i v), (C) \to (i), (D) \to (i i)$
$(A) \to (i i), (B) \to (i i i), (C) \to (i v), (D) \to (i)$

Toppr Admin · Accepted Answer

-xA0-Carbylamine reaction-A- CH3NH2-CHCl3-KOH-x394-x2212-x2192-CH3NCHoffman Bromamide reaction-B- CH3CONH2-Br2-KOH-x2192-CH3NH2Reaction with HNO2-c- CH3NH2-NaNO2-HCl-x2192-CH3OHReduction-xA0- with H2-Pt-D- CH3NC-4HPt-Pd-x2212-x2212-x2212-x2212-x2192-CH3NHCH3Option C is correct-

	Column I		Column II
$(A)$	$C H_{3} N H_{2} + C H C l_{3} + K O H Δ - \to$	$(i)$	$C H_{3} N H_{2}$
$(B)$	$C H_{3} C O N H_{2} + B r_{2} + K O H \to$	$(i i)$	$C H_{3} O H$
$(C)$	$C H_{3} N H_{2} + N a N O_{2} + H C l \to$	$(i i i)$	$C H_{3} N H C H_{3}$
$(D)$	$C H_{3} N C + 4 H P t - \to$	$(i v)$	$C H_{3} N C$

Carbylamine reaction:(A) CH3NH2+CHCl3+KOHΔ−→CH3NCHoffman Bromamide reaction:(B) CH3CONH2+Br2+KOH→CH3NH2Reaction with HNO2(c) CH3NH2+NaNO2+HCl→CH3OHReduction with H2/Pt:(D) CH3NC+4HPt/Pd−−−−→CH3NHCH3Option C is correct.