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Question

Match the column I with column II and mark the appropriate choice.
column Icolumn II
ANaHiInterstitial hydride
BCH4iiMolecular hydride
CVH0.56iiiIonic hydride
DB2H6iv Electron-deficient hydride

  1. (A)(iii),(B)(iv),(C)(ii)(D)(i)
  2. (A)(ii),(B)(iv),(C)(iii)(D)(i)
  3. (A)(i),(B)(ii),(C)(iv)(D)(iii)
  4. (A)(iii),(B)(ii),(C)(i)(D)(iv)

A
(A)(iii),(B)(iv),(C)(ii)(D)(i)
B
(A)(ii),(B)(iv),(C)(iii)(D)(i)
C
(A)(i),(B)(ii),(C)(iv)(D)(iii)
D
(A)(iii),(B)(ii),(C)(i)(D)(iv)
Solution
Verified by Toppr

NaH is an ionic compound and is made of sodium cations (Na+) and hydride anions (H). It has the octahedral crystal structure with each sodium ion surrounded by six hydride ions.

CH4 forms molecular or covalent hydrides. These are mainly formed by p - block elements and some s - block elements.

The third compound has an oxidation number of hydrogen which is zero. So it belongs to Interstitial hydride.

In B2H6 the Boron atom is surrounded by 6 electrons, so it is electron deficient due to its incomplete octet.

The correct option is D.

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