Match the followingColumn -A-Column -B-a-NaHCO-3-i-Caustic soda-b-Na-2CO-3-10H-2O-ii-Baking soda-c-NaOH-iii-Blue vitriol-d-CuSO-4- 5H-2O-iv-Washing sodaa-i- b-ii- c-iii- d-iv-a-ii- b-iv- c-i- d-iii-a-i- b-iv- c-ii- d-iii-a-ii- b-iv- c-iii- d-i-

Question

Toppr Admin · Accepted Answer

NaHCO3-x27F6- Baking soda -Sodium Bi-carbonate-Na2CO3-x22C5-10H2O-x27F6- Washing soda -Sodium carbonate deca-hydrate-NaOH-x27F6- Caustic soda -Sodium hydroxide-CuSO4-x22C5-5H2O-x27F6- Blue vitriol -Copper sulphate pentahydrate-Hence- option B is correct-

	Column (A)		Column (B)
(a)	$N a H C O_{3}$	(i)	Caustic soda
(b)	$N a_{2} C O_{3} .10 H_{2} O$	(ii)	Baking soda
(c)	$N a O H$	(iii)	Blue vitriol
(d)	$C u S O_{4} . 5 H_{2} O$	(iv)	Washing soda

	Column (A)		Column (B)
(a)	$N a H C O_{3}$	(i)	Caustic soda
(b)	$N a_{2} C O_{3} .10 H_{2} O$	(ii)	Baking soda
(c)	$N a O H$	(iii)	Blue vitriol
(d)	$C u S O_{4} . 5 H_{2} O$	(iv)	Washing soda

Match the followingColumn (A)Column (B)(a)NaHCO3(i)Caustic soda(b)Na2CO3.10H2O(ii)Baking soda(c)NaOH(iii)Blue vitriol(d)CuSO4.5H2O(iv)Washing sodaa-(i), b-(ii), c-(iii), d-(iv)a-(ii), b-(iv), c-(i), d-(iii)a-(i), b-(iv), c-(ii), d-(iii)a-(ii), b-(iv), c-(iii), d-(i)

NaHCO3⟶ Baking soda (Sodium Bi-carbonate)Na2CO3⋅10H2O⟶ Washing soda (Sodium carbonate deca-hydrate)NaOH⟶ Caustic soda (Sodium hydroxide)CuSO4⋅5H2O⟶ Blue vitriol (Copper sulphate pentahydrate)Hence, option B is correct.

$N a H C O_{3} ⟶$ Baking soda (Sodium Bi-carbonate)
$N a_{2} C O_{3} \cdot 10 H_{2} O ⟶$ Washing soda (Sodium carbonate deca-hydrate)
$N a O H ⟶$ Caustic soda (Sodium hydroxide)
$C u S O_{4} \cdot 5 H_{2} O ⟶$ Blue vitriol (Copper sulphate pentahydrate)
Hence, option $B$ is correct.