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Question
\( \mathrm { ABCD } \) is a parallelogram, \( \mathrm { M } \) is the mid - point of \( \mathrm { BD } \) and \( \mathrm { BM } \) bisects \( \angle \mathrm { B } _ { 1 } \) then \( \angle \mathrm { AMB } = \) (A) \( 45 ^ { \circ } \) fer \( 90 ^ { \circ } \) (B) \( 60 ^ { \circ } \) (D) \( 75 ^ { \circ } \)
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Q1
ABCD is a parallelogram, M is the mid-point of BD and BM bisects ∠B. Then ∠AMB=
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Q2
In the given figure, ABCD is a parallelogram, M is the mid-point of BD and BD bisects ā B as well as ā D. Then, ā AMB = ?
(a) 45Ā°
(b) 60Ā°
(c) 90Ā°
(d) 30Ā°