Mathrm-M-mathrm-C-l-4-xrightarrow-Zn-heat- Purple colour compound -Colourless -A-liquid-mathrm-M- Transition metaldownarrow mathrm-M-mathrm-o-mathrm-i-mathrm-s-mathrm-t- air-B-White fumesIdentify -A- -B- and mathrm-M-mathrm-C-l-4- Also explain colour difference between mathrm-M-mathrm-C-l-4- and -A-

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Toppr Admin · Accepted Answer

TiCl4heat-x2212-x2212-x2192-ZnTiCl3-x2212-x2212-x2192-H2O-Ti-H2O-6-Cl3 Purple color -A-TiCl4-n-2-H2O -moist air-x27F6-TiO2-H2O-n-4HCl-x2191- white fumes -B-Ti4-Ar-3d-xB0-Ti3-Ar-3d1Ti -IV- ion contains no d-electron- while d-d-transition of single electron in Ti -III- causes color change-

MCl4heat−−→Zn Purple colour compound (Colourless (A)liquid)M= Transition metal↓Moist air(B)White fumesIdentify (A), (B) and MCl4. Also explain colour difference between MCl4 and (A).

TiCl4heat−−→ZnTiCl3−−→H2O[Ti(H2O)6]Cl3 Purple color (A)TiCl4+(n+2)H2O (moist air)⟶TiO2(H2O)n+4HCl↑ white fumes (B)Ti4+=[Ar]3d°Ti3+=[Ar]3d1Ti (+IV) ion contains no d-electron, while d-d-transition of single electron in Ti (+III) causes color change.

$M C l_{4} h e a t - - \to Z n$ Purple colour compound (Colourless (A)
liquid)
$M =$ Transition metal
$↓ M o i s t$ air
(B)
White fumes
Identify (A), (B) and $M C l_{4}$ . Also explain colour difference between $M C l_{4}$ and (A).