Measure of angle y is-55-circ-75-circ-45-circ-65-circ-

Question

Toppr Admin · Accepted Answer

We know that- the measure of exterior angle of triangle-xA0-is equal to sum of the remote interior angles-x2234-x2220-ACD-x2220-BAC-x2220-ABC-x2234-115o-40o-y-x2234-y-115-x2218-x2212-40-x2218-x2234-y-75-x2218-So- option B is correct-

Weight	$45 - 55$	$55 - 65$	$65 - 75$	$75 - 85$	$85 - 95$
Number of persons	$1$	$2$	$3$	$10$	$7$

Weight	No of students
$40 - 45$	$2$
$45 - 50$	$3$
$50 - 55$	$8$
$55 - 60$	$6$
$60 - 65$	$6$
$65 - 70$	$3$
$70 - 75$	$2$

Measure of $∠ y$ is:

$55^{\circ}$
$75^{\circ}$
$45^{\circ}$
$65^{\circ}$

We know that, the measure of exterior angle of triangle
is equal to sum of the remote interior angles.
$∴ ∠ A C D = ∠ B A C + ∠ A B C$
$∴ 115^{o} = 40^{o} + y$
$∴ y = 115^{\circ} - 40^{\circ}$
$∴ y = 75^{\circ}$
So, option B is correct.

Measure of ∠y is:55∘75∘45∘65∘

We know that, the measure of exterior angle of triangle is equal to sum of the remote interior angles.∴∠ACD=∠BAC+∠ABC∴115o=40o+y∴y=115∘−40∘∴y=75∘So, option B is correct.

Measure of $∠ y$ is:

$55^{\circ}$
$75^{\circ}$
$45^{\circ}$
$65^{\circ}$

We know that, the measure of exterior angle of triangle
is equal to sum of the remote interior angles.
$∴ ∠ A C D = ∠ B A C + ∠ A B C$
$∴ 115^{o} = 40^{o} + y$
$∴ y = 115^{\circ} - 40^{\circ}$
$∴ y = 75^{\circ}$
So, option B is correct.