Measures (in degree) of two complementary angles are two consecutive even integers. Find the angles.
Let one angle be $$2y$$ and other angle be $$2y+2^o$$.
As we know, the sum of complementary angles is $$90^o$$
Then,
$$\Rightarrow 2y+(2y+2^o)=90^o$$
$$\Rightarrow 2y+2y+2^o=90^o$$
$$\Rightarrow 4y=90^o-2^o$$
$$\Rightarrow 4y=88^o$$
$$\Rightarrow y=\dfrac{88^o}{4}$$
$$\Rightarrow y=22^o$$.
$$\therefore 2y=2 \times 22^o =44^o$$
and $$2y+2=44^o+2=46^o$$.
Therefore, one angle is $$44^o$$ and other angle is $$46^o$$.