0
You visited us 0 times! Enjoying our articles? Unlock Full Access!
Question

- Medical Chemistry The solubility of BaSO4 in water 2.42 x 10 gL at 298 K. The value of solubility product (Ksp) will be (Given molar mass of BaSO4 = 233 g moll) (1) 1.08 x 10-10 moll L-2 (2) 1.08 x 10-12 mol2 L-2 (3) 1.08 x 10-14 mol2 L-2 (4) 1.08 x 10-8 mol? L-2

Solution
Verified by Toppr


Was this answer helpful?
0
Similar Questions
Q1
The solubility of BaSO4 in water is 2.42 × 103 gL1 at 298 K. The value of its solubility product (Ksp) will be
(Given molar mass ofBaSO4 = 233 g mol–1)
View Solution
Q2
The solubility of BaSO4 in water is 2.42 × 103 gL1 at 298 K. The value of its solubility product (Ksp) will be
(Given molar mass ofBaSO4 = 233 g mol–1)
View Solution
Q3
Calculate the solubility of a sparingly soluble compund A2X3 at 25C.
The solubility product Ksp of A2X3 is 1.08×1023 at the given temperature.
View Solution
Q4
The solubility of BaSO4 in water is 2.42×103gL1 at 298 K. The value of its solubility product (Ksp) will be:
(Given molar mass of BaSO4=233 gmol1).
View Solution
Q5
The solubility of BaSO4 in water is 2.42×103 g L1 at 298 K. The value of its solubility product (Ksp) will be:
(Given molar mass of BaSO4=233 g mol1)

<!--td {border: 1px solid #cccccc;}br {mso-data-placement:same-cell;}--> NEET 2018
View Solution