Metal X form 2 oxide. Formula of 1st is XO21st oxide contain 50%O2. If 2nd oxide contain 60%O2 .Formula of 2nd oxide?
X2O
XO3
X2O3
X3O2
A
X2O3
B
X3O2
C
X2O
D
XO3
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Solution
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The correct option is CX2O3 Given that inXO2,50% of O2 is present
2O2=3232M+32=0.5
now ,given that is second oxide 60% of is present let no. of metal X contained in this oxide.is n then,
32n×32+32=0.61n+1=0.61=0.6n+0.6n=0.40.6=23X2O3
is formula of compound
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