-MF - Xe F-4rightarrow - -A- -M- text-Alkali metal cation-The state of hybridisation of the central atom in -A- and shape of the species are -sp-3d- TBP-sp-3d-3- distorted octahedral-sp-3d-3-pentagonal planarNo compound formed all

Question

Toppr Admin · Accepted Answer

Here- M2XeF6 forms as product- which has-xA0-sp3d3 hybridization and-xA0-pentagonal planar structure-

(i)	$X e F_{2}$	(a)	Central atom is $s p^{3}$ hybridised and has a bent shape.
(ii)	$N_{3}^{-}$	(b)	Central atom is $s p^{3} d^{2}$ hybridised and has an octahedral shape.
(iii)	$P C l_{6}^{-}$	(c)	Central atom is $s p$ hybridised and has a linear shape.
(iv)	$I C l_{2}^{+}$	(d)	Central atom is $s p^{3} d$ hybridised and has a linear shape.

$M F + X e F_{4} \to$ 'A'
( $M^{+} = Alkali metal cation)$
The state of hybridisation of the central atom in 'A' and shape of the species are :
$s p^{3} d$ , TBP
$s p^{3} d^{3}$ , distorted octahedral
$s p^{3} d^{3}$ ,pentagonal planar
No compound formed at all

Here, $M_{2} X e F_{6}$ forms as product, which has $s p^{3} d^{3}$ hybridization and pentagonal planar structure.

MF+XeF4→ 'A' (M+=Alkali metal cation)The state of hybridisation of the central atom in 'A' and shape of the species are :sp3d, TBPsp3d3, distorted octahedralsp3d3,pentagonal planarNo compound formed at all

Here, M2XeF6 forms as product, which has sp3d3 hybridization and pentagonal planar structure.

$M F + X e F_{4} \to$ 'A'
( $M^{+} = Alkali metal cation)$
The state of hybridisation of the central atom in 'A' and shape of the species are :
$s p^{3} d$ , TBP
$s p^{3} d^{3}$ , distorted octahedral
$s p^{3} d^{3}$ ,pentagonal planar
No compound formed at all

Here, $M_{2} X e F_{6}$ forms as product, which has $s p^{3} d^{3}$ hybridization and pentagonal planar structure.