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Question

Multiply $$2\sqrt{6}$$ by $$3\sqrt{3}$$.

Solution
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$$2\sqrt{6}\times 3\sqrt{3}$$

It can also be written as

$$=2\times 3\times \sqrt{6}\times \sqrt{3}$$

$$=6\times \sqrt{6\times 3}$$

So we get

$$=6\times \sqrt{2\times 3\times 3}$$

By multiplication

$$=6\times 3\sqrt{2}$$

$$2\sqrt{6}\times 3\sqrt{3}$$$$=18\sqrt{2}$$.

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