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"N. ABCD is a parallelogram and \\( \\mathrm { E } \\) is the\npoint on \\( \\mathrm { CD } \\), such that \\( \\mathrm { CE } = 2 \\mathrm { ED } \\). A \\( \\mathrm { E } \\) is\njoined meeting \\( \\mathrm { BD } \\) in \\( \\mathrm { F } \\) and \\( \\mathrm { BC } \\) produced\nin G. Prove that \\( \\mathrm { AG } = 4 \\mathrm { AF } \\).\n\\[ \\frac { \\mathrm { A } } { \\mathrm { B } } \\frac { \\mathrm { f } ^ { 2 } \\text { . } } { \\mathrm { C } } \\text { . } \\mathrm { G } \\]"

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