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Question
(n+1)*-(n-1)" (n+1)* +(n-1) se is equal to (A)-1 (B) (C) (D)DNE
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Similar Questions
Q1
∣
∣ ∣ ∣
∣
a
+
b
+
n
c
(
n
−
1
)
a
(
n
−
1
)
b
(
n
−
1
)
c
b
+
c
+
n
a
(
n
−
1
)
b
(
n
−
1
)
c
(
n
−
1
)
a
(
c
+
a
+
n
b
)
∣
∣ ∣ ∣
∣
is equal to
View Solution
Q2
The value of
∣
∣ ∣ ∣
∣
(
−
1
)
n
a
(
−
1
)
n
+
1
b
(
−
1
)
n
+
1
c
a
+
1
1
−
b
1
+
c
a
−
1
b
+
1
1
−
c
∣
∣ ∣ ∣
∣
+
∣
∣ ∣ ∣
∣
(
−
1
)
n
+
1
a
a
+
1
a
−
1
(
−
1
)
n
b
1
−
b
b
+
1
(
−
1
)
n
+
2
c
1
+
c
1
−
c
∣
∣ ∣ ∣
∣
is equal to ..............
View Solution
Q3
If
1
≤
r
≤
n
then
n
n
−
1
C
r
−
1
is equal to .........
View Solution
Q4
The value of
∑
r
=
1
n
(
2
r
-
1
)
a
+
1
b
r
is equal to
(a)
a
n
2
+
b
n
-
1
-
1
b
n
-
1
(
b
-
1
)
(b)
a
n
2
+
b
n
-
1
b
n
(
b
-
1
)
(c)
a
n
3
+
b
n
-
1
-
1
b
n
(
b
-
1
)
(d) none of these
View Solution
Q5
If S
n
=
∑
r
=
1
n
1
+
2
+
2
2
+
.
.
.
Sum
to
r
terms
2
r
, then S
n
is equal to
(a) 2
n
− n − 1
(b)
1
-
1
2
n
(c)
n
-
1
+
1
2
n
(d) 2
n
− 1
View Solution
