Given- A-3 and Q-8-xA0- -xA0-As per the given condition- we haveA-A-B and B-N-Q-x2234-2A-B and B-N-8-x2234-B-6 and 6-N-8-x2234-N-2-x2234-N2-22-4

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Standard XII

Mathematics

Question

$N^{2}$ = ?
$16$
$4$
$1$
$9$

16

1

4

9

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Solution

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Given, $A = 3$ and $Q = 8$
As per the given condition, we have
$A + A = B$ and $B + N = Q$
$∴ 2 A = B$ and $B + N = 8$
$∴ B = 6$ and $6 + N = 8$
$∴ N = 2$
$∴ N^{2} = 2^{2} = 4$

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Given, A=3 and Q=8 As per the given condition, we haveA+A=B and B+N=Q∴2A=B and B+N=8∴B=6 and 6+N=8∴N=2∴N2=22=4

$N^{2}$ = ?
$16$
$4$
$1$
$9$

Given, $A = 3$ and $Q = 8$
As per the given condition, we have
$A + A = B$ and $B + N = Q$
$∴ 2 A = B$ and $B + N = 8$
$∴ B = 6$ and $6 + N = 8$
$∴ N = 2$
$∴ N^{2} = 2^{2} = 4$