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chemistry

is 25% dissociated at and one atmosphere pressure. Calculate and the percentage dissociation at atmosphere and .

A

0.166 atm and 37% respecively

B

0.266 atm and 87% respectively

C

0.316 atm and 47% respectively

D

0.316 atm and 37% respectively

Video Explanation

Answer

Let initially 1 mole of be present. Total pressure is 1 atm.







 Initial moles  
 Equilibrium moles  
The expression for the equilibrium constant is:
Now total pressure is 0.1 atm. 
 
Equilibrium moles are
Mole fraction are ,  
The expression for the equilibrium constant is . . Thus . Hence, the degree of dissociation is 87%.

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