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Question

Normality of 0.3 M phosphorus acid (H3PO3) is:
  1. 0.5
  2. 0.6
  3. 0.9
  4. 0.1

A
0.5
B
0.6
C
0.1
D
0.9
Solution
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For acids, Normality = molarity×basicity

So, Normality = 0.3×2=0.6

Basicity of H3PO3 is 2 because one of the H is not replaceable in H3PO3. The H atoms which are linked to oxygen are replaceable, but H atom linked directly to central atom P is nonreplaceable.

Hence, the correct option is B

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