Number of coulombs of current required to convert completely convert one mole of
MnO $_{4}^{-}$ ions in acid medium to one mole of Mn $^{2 +}$ ions electrolytically is:

Question

Number of coulombs of current required to convert completely convert one mole of MnO-4- ions in acid medium to one mole of Mn-2- ions electrolytically is-965005x9650096500x696500x2

Toppr Admin · Accepted Answer

MnO-x2212-4-x2192-Mnt2-5e-x2212-5 moles of e-x2212-xA0- are released-x2234- 5 faraday of charge is released charge -5-xD7-96500Hence- option B is correct-

Number of coulombs of current required to convert completely convert one mole of
MnO $_{4}^{-}$ ions in acid medium to one mole of Mn $^{2 +}$ ions electrolytically is:

96500
5x96500
96500x6
96500x2

$M n O_{4}^{-} \to M n^{t 2} + 5 e^{-}$
5 moles of $e^{-}$ are released
$∴$ 5 faraday of charge is released charge $= 5 \times 96500$
Hence, option B is correct.

Number of coulombs of current required to convert completely convert one mole of MnO−4 ions in acid medium to one mole of Mn2+ ions electrolytically is:965005x9650096500x696500x2

MnO−4→Mnt2+5e−5 moles of e− are released∴ 5 faraday of charge is released charge =5×96500Hence, option B is correct.

Number of coulombs of current required to convert completely convert one mole of
MnO $_{4}^{-}$ ions in acid medium to one mole of Mn $^{2 +}$ ions electrolytically is:

96500
5x96500
96500x6
96500x2

$M n O_{4}^{-} \to M n^{t 2} + 5 e^{-}$
5 moles of $e^{-}$ are released
$∴$ 5 faraday of charge is released charge $= 5 \times 96500$
Hence, option B is correct.