Number of nuclei of a radioactive substance at time t = 0 are 1000 and 900 at time t = 2s. What will be the number of nuclei at time t = 4s?

Question

Number of nuclei of a radioactive substance are 1000 and 900 times t-0 and time t-2 s- Then- number of nuclei time t-4 s will be800810790700

Toppr Admin · Accepted Answer

Every 2s-xA0-10- of the substance decays- i-e-After 2s there are 900 nuclei- after 2 more seconds- it must reduce by 10- which means 0-9-xD7-900-810 nuclei would remain-xA0-

Number of nuclei of a radioactive substance are $1000$ and $900$ at times $t = 0$ and time $t = 2 s$ . Then, number of nuclei at time $t = 4 s$ will be
$800$
$810$
$790$
$700$

Every $2 s 10$ % of the substance decays, i.e.
After $2 s$ there are $900$ nuclei, after $2$ more seconds, it must reduce by $10$ %, which means $0.9 \times 900 = 810$ nuclei would remain.

Number of nuclei of a radioactive substance are 1000 and 900 at times t=0 and time t=2s. Then, number of nuclei at time t=4s will be800810790700

Every 2s 10% of the substance decays, i.e.After 2s there are 900 nuclei, after 2 more seconds, it must reduce by 10%, which means 0.9×900=810 nuclei would remain.

Number of nuclei of a radioactive substance are $1000$ and $900$ at times $t = 0$ and time $t = 2 s$ . Then, number of nuclei at time $t = 4 s$ will be
$800$
$810$
$790$
$700$

Every $2 s 10$ % of the substance decays, i.e.
After $2 s$ there are $900$ nuclei, after $2$ more seconds, it must reduce by $10$ %, which means $0.9 \times 900 = 810$ nuclei would remain.