Number of unpaired electrons of neutral manganese atom and its divalent ion are in the ratio (the atomic number of manganese is 25 and it loses two electrons to form the divalent ion):

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Answer 1

Manganese atom has 5 electrons in 3d orbital and two electrons in 4s orbital.It has five unpaired electrons. In its +2 oxidation state, the two '4s' electrons are lost and it has five unpaired electrons.

Answer 2

Manganese atom has 5 electrons in 3d orbital and two electrons in 4s orbital.It has five unpaired electrons. In its +2 oxidation state, the two '4s' electrons are lost and it has five unpaired electrons.

Number of unpaired electrons of neutral manganese atom and its divalent ion are in the ratio (the atomic number of manganese is 25 and it loses two electrons to form the divalent ion):

$1 : 1$

$25 : 23$

$5 : 3$

$3 : 5$

Manganese atom has 5 electrons in 3d orbital and two electrons in 4s orbital.It has five unpaired electrons. In its +2 oxidation state, the two '4s' electrons are lost and it has five unpaired electrons.

Which of the following has maximum number of unpaired electrons?

The number of unpaired electrons in $M n^{4 +}$ ( $z =$ 25) is :

The number of unpaired electrons in chromium atom are :

The ratio of $e / m$ for $H^{+}$ and $H e^{2 +}$ is :

Nickel atom can lose two electrons to form $N i^{2 +}$ ion. The atomic number of nickel is 28. From which orbital it can lose two electrons?

Revise with Concepts

Electron Configuration

Number of unpaired electrons of neutral manganese atom and its divalent ion are in the ratio (the atomic number of manganese is 25 and it loses two electrons to form the divalent ion):

1:1

25:23

5:3

3:5

Manganese atom has 5 electrons in 3d orbital and two electrons in 4s orbital.It has five unpaired electrons. In its +2 oxidation state, the two '4s' electrons are lost and it has five unpaired electrons.

Which of the following has maximum number of unpaired electrons?

The number of unpaired electrons in Mn4+(z=25) is :

The number of unpaired electrons in chromium atom are :

The ratio of e/m for H+ and He2+ is :

Nickel atom can lose two electrons to form Ni2+ ion. The atomic number of nickel is 28. From which orbital it can lose two electrons?

Revise with Concepts

Electron Configuration

$1 : 1$

$25 : 23$

$5 : 3$

$3 : 5$

The number of unpaired electrons in $M n^{4 +}$ ( $z =$ 25) is :

The ratio of $e / m$ for $H^{+}$ and $H e^{2 +}$ is :

Nickel atom can lose two electrons to form $N i^{2 +}$ ion. The atomic number of nickel is 28. From which orbital it can lose two electrons?