+ - o 121-11 <1 then (24+3/1+2s lies in Jarpe

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Similar Questions

Which of the following orbitals is of the leastenergy?(2) 2s (B)(1) 2s (Li)(4) 2s (N)(3) 2s (F)

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Consider the following nuclear reactions:
1.

_{7}^{14} N +_{2}^{4} H e ⟶

_{8}^{17} O +_{1}^{1} H

_{4}^{9} B e +_{1}^{1} H ⟶

_{3}^{9} L i +_{2}^{4} H e

_{12}^{24} M g +_{2}^{4} H e ⟶

_{14}^{27} S i +_{0}^{1} n

_{5}^{10} B +_{2}^{4} H e ⟶

_{7}^{13} N +_{0}^{1} n

Examples of induced radioactivity would include the reactions:

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y = {sin}^{- 1} (x \sqrt{1 - x} - \sqrt{x} \sqrt{1 - x^{2}}} and 0 < x < 1, then \frac{dy}{dx}

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The equilibrium constant,

k_{p}

for the reaction;

2 S O_{2 (g)} + O_{2 (g)} \to 2 S O_{3 (g)}

7.1] t i m e s 10^{24}

298 K

. Calculate

Δ G^{o}

for the reaction.
(Given

: R = 8.314 J K - 1 m o l^{- 1})

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Go back to Pascal's triangle.
Line-

1

1 = 11^{o}

Line-

2

11 = 11^{1}

Line-

3

121 = 11^{2}

Make a conjecture about Line-

4

and Line-

5

.
Does your conjecture hold? Does your conjecture hold for Line-

6

too?

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