Question

Object Pin | Convex Lens | Convex Mirror | Image Pin |

22.2 cm | 32.2 cm | 45.8 cm | 71.2 cm |

The focal length of the convex lens is $f_{1}$ and that of mirror is $f_{2}$. Then taking index correction to be negligibly small, $f_{1}$ and $f_{2}$ are close to :

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Updated on : 2022-09-05

Solution

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Correct option is A)

$v1 +101 =f_{1}1 $ ... (1)

For mirror,

$25.41 −45.8−32.2−v1 =f_{2}1 $

$25.41 −13.6−v1 =f_{2}1 $ .... (2)

Since there are 3 variables and only two equations (1) and (2) therefore only by substituting $f_{1}$ & $f_{2}$ from options correct values can be verified.

Eliminating $v$ from the equation (1), we get a relation between $f_{1}$ and $f_{2}$. This relation is satisfied only by option A.

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