Question

Of the isomeric hexanes, the isomers that give the minimum and the maximum number of monochloro derivatives are respectively :

• A. 2,3- dimethylbutane and n - hexane
• B. 2-methylpentane and 2,2-dimethylbutane
• C. 3 - methylpentane and 2,3- dimethylbutane
• D. 2,3 - dimethylbutane and 2 - methylpentane
• E. 2,2- dimethylbutane and 2 - methylpentane

Answer 1

Answer: (D)

The possible isomers of hexane are (i) (ii) (iii) (iv) Out of these structure (iii) and (i) have respectively minimum and maximum number of monochloroderivatives For structure (iii), (a) (b) [Only 2 monochloroderivatives (minimum) are possible] For structure (i), (a) (b) (c) (d) [5 monochloroderivatives (maximum) are possible]