On compressing a gas suddenly- its temperature increasesdecreasesremains constantall the above

Question

Toppr Admin · Accepted Answer

From the First-xA0-Law-xA0-of-xA0-Thermodynamics-dQ-dU-dWSudden processes in ideal gases are adiabatic- So- dQ - 0-So- dU - - dW-xA0-In compression of an ideal gas- dW -lt- 0So- dU -gt- 0 hence dT -gt- 0

On compressing a gas suddenly, its temperature
increases
decreases
remains constant
all the above

From the $F i r s t L a w o f T h e r m o d y n a m i c s, d Q = d U + d W$
Sudden processes in ideal gases are adiabatic. So, dQ = 0.
So, dU = - dW
In compression of an ideal gas, dW < 0
So, dU > 0 hence dT > 0

On compressing a gas suddenly, its temperature increasesdecreasesremains constantall the above

From the First Law of Thermodynamics,dQ=dU+dWSudden processes in ideal gases are adiabatic. So, dQ = 0.So, dU = - dW In compression of an ideal gas, dW < 0So, dU > 0 hence dT > 0

On compressing a gas suddenly, its temperature
increases
decreases
remains constant
all the above

From the $F i r s t L a w o f T h e r m o d y n a m i c s, d Q = d U + d W$
Sudden processes in ideal gases are adiabatic. So, dQ = 0.
So, dU = - dW
In compression of an ideal gas, dW < 0
So, dU > 0 hence dT > 0