On a certain field day- Nitin jumped 4displaystyle-frac-7-12- feet and Anil jumped 3displaystyle-frac-1-6- feet- How much farther did Nitin jump than Anil - 1displaystyle-frac-5-6- feet1displaystyle-frac-5-12- feetdisplaystyle-frac-5-12- feet2 feet

Question

Toppr Admin · Accepted Answer

Nitin jumped -4712feetAnil jumped -316feetRequired Difference-xA0-4712-x2212-316-5512-x2212-196-55-x2212-3812-xA0- -xA0- -xA0- -xA0- -xA0- -xA0- -xA0- - LCM-6-12-12 -1712-1512-xA0-feetHence- this is the answer-

On a certain field day, Nitin jumped 4 $\frac{7}{12}$ feet and Anil jumped 3 $\frac{1}{6}$ feet. How much farther did Nitin jump than Anil ?
1 $\frac{5}{6}$ feet
1 $\frac{5}{12}$ feet
$\frac{5}{12}$ feet
2 feet

Nitin jumped $= 4 \frac{7}{12} f e e t$

Anil jumped $= 3 \frac{1}{6} f e e t$

Required Difference:
$= 4 \frac{7}{12} - 3 \frac{1}{6}$

$= \frac{55}{12} - \frac{19}{6}$

$= \frac{55 - 38}{12}$ { LCM $(6, 12) = 12$ }

$= \frac{17}{12}$

$= 1 \frac{5}{12} f e e t$

Hence, this is the answer.

On a certain field day, Nitin jumped 4712 feet and Anil jumped 316 feet. How much farther did Nitin jump than Anil ? 156 feet1512 feet512 feet2 feet

Nitin jumped =4712feetAnil jumped =316feetRequired Difference: =4712−316=5512−196=55−3812 { LCM(6,12)=12 }=1712=1512 feetHence, this is the answer.

On a certain field day, Nitin jumped 4 $\frac{7}{12}$ feet and Anil jumped 3 $\frac{1}{6}$ feet. How much farther did Nitin jump than Anil ?
1 $\frac{5}{6}$ feet
1 $\frac{5}{12}$ feet
$\frac{5}{12}$ feet
2 feet

Nitin jumped $= 4 \frac{7}{12} f e e t$

Anil jumped $= 3 \frac{1}{6} f e e t$

Required Difference:
$= 4 \frac{7}{12} - 3 \frac{1}{6}$

$= \frac{55}{12} - \frac{19}{6}$

$= \frac{55 - 38}{12}$ { LCM $(6, 12) = 12$ }

$= \frac{17}{12}$

$= 1 \frac{5}{12} f e e t$

Hence, this is the answer.