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Catalytic Hydrogenation

Question

On heating sodium propionate with sodalime the hydrocarbon obtained is:
butane
ethane
propane
ethene

A

butane

B

ethane

C

propane

D

ethene

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Solution

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Sodium propionate reacts with soda lime (NaOH+CaO) to form ethane.

The reaction can be given as follows:

$C_{2} H_{5} C O O N a s o d i u m p r o p i o n a t e + N a O H C a O / Δ - --- \to C H_{3} - C H_{3} + N a_{2} C O_{3}$

Option $(B)$ is correct.

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